A car is traveling around a horizontal circular track with radius r = 240 m at a

Question

A car is traveling around a horizontal circular track with radius r = 240 m at a constant speed v = 25 m/s as shown. The angle A = 29° above the x axis, and the angle B = 59° below the x axis.

1)What is the magnitude of the car’s acceleration?

2) What is the x component of the car’s acceleration when it is at point A

3) What is the y component of the car’s acceleration when it is at point A

4) What is the x component of the car’s acceleration when it is at point B

5) What is the y component of the car’s acceleration when it is at point B

6) As the car passes point B, the y component of its acceleration is

a) increasing b) constant c) decreasing

Explanation / Answer

(a) a= v^2/r = (252/(240) = 2.604 m/s^2

(b)x component =(-2.604)(cos 29) = -2.2777 m/s2

(c) y component = (2.604)(sin29) = 1.262m/s^2

(d) x component = (2.604)(cos 59) = -1.341m/s^2

(e) y component = (2.604)(sin 59) = 2.232m/s^2

(f)As the car passes point B, its y component of acceleration is decreasing.

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