The distance between the objective and eyepiece lenses in a microscope is 25 cm

Question

The distance between the objective and eyepiece lenses in a microscope is 25 cm . The objective lens has a focal length of 6.00 mm and the eyepiece lens has a focal length of 7.5 cm .

Part A If the object is placed 6.20 mm in front of the objective lens, where is the final image formed?

Part B What is the total linear magnification for the microscope?

Part C What is the overall angular magnification for the microscope if the eye is placed at the second lens?

***This has been posted multiple times and answered incorrectly every time. Please help. Thank you!***

Yet again this was answered incorrectly...if you're not sure, please don't solve this. Thanks.

Explanation / Answer

Part C :

Angualar magnification of eye piece = Me = 25./ fe
Me = 25/ 7.5 =3.33

Part B :

  Linear magnification of objective mo= -L/fo = - 25/0.6 cm = - 41.66

Part A:

   1/f = 1/s + 1/s'

Where f is the focal length, s is distance from the object, and s' is the distance from the image.

There's two lenses, so you'll have to do this twice.

For the first one: plug in the values:

f = 7.5 cm
s = 0.62 cm
s' = What we're gonna solve for

1/7.5 = 1/0.62 + 1/s'

s' = - 0.674cm

negative sign means that it is in front of the lens.

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