The displacement x(t) of a cart of a mass-spring system is described by the diff
ID: 3142183 • Letter: T
Question
The displacement x(t) of a cart of a mass-spring system is described by the differential equation d^2/dt^2 + 8 dx/dt + 15 x = 0 with the following Initial conditions: x (0) = 10. dx/dt (0) = 80. Calculate the maximum value of the displacement x(t) (for positive values of time t), round it off to three significant decimal digits, and provide the result. A student found that the result was as follows (your numerical answer must be written here) you must provide some intermediate results obtained by you while solving the problem above:Explanation / Answer
The given equation is
x'' + 8x' + 15x = 0
The characteristic equation is r2 + 8r + 15 = 0
=> r2 + 5r + 3r + 15 = 0
=> r (r + 5) + 3 (r + 5) = 0
=> (r + 5) (r + 3) = 0
=> r = -5 and r = -3
Let x(t) = ae-5t + be-3t
When t = 0
x(0) = a + b = 10
Multiplying by 5
=> 5a + 5b = 50 (1)
Differentiating x(t)
x'(t) = -5ae-5t -3be-3t
When t = 0
x'(0) = -5a -3b = 80 (2)
Adding (1) and (2)
=> 2b = 130 => b = 65
Substituting in (1)
=> 5a + 5*65 = 50
=> 5a + 325 = 50
=> a = -275/5 = -55
Thus the solution is x(t) = -55e-5t + 65e-3t
Displacement x is maximum when x'(t) = 0
=> -5ae-5t -3be-3t = 0
Multiplying by e5t
=> -5a -3be2t = 0
=> e2t = -5a/3b
= -(5*-55) / (3*65)
= 275/195 = 1.41
=> 2t = ln 1.41 = 0.3435
=> t = 0.1718
Thus x(t) = -55e-5*0.1718 + 65e-3*0.1718
= -55e-0.859 + 65e-0.5154
= 85.533
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.