A massless string is tied up, erect, between block A. of mass m_1 - 2 kg, at its

Question

A massless string is tied up, erect, between block A. of mass m_1 - 2 kg, at its left and block B, of mass m_1 - 3kg, at its right. The system is placed on a horizontal ground. A force F = 20N is parallel to the ground and pulls the system by acting on block B toward the right i. e. in the x - direction. The coefficient of friction between each block and the ground is mu = 0.5. Draw a free body diagram for each block. Calculate the magnitude of the acceleration of the system as it moves along the ground. Calculate the tension in the string during the above motion of the two blocks.

Explanation / Answer

(a) ans

the free body diagram

[2 kg]------------------------->T<----------------------[3 kg]---------->F

(b) ans

the acceleration of the blocks

F-µ(m1+m2)=(m1+m2)a

20-0.5(2+3)=(2+3)a

20-2.5=5a

17.5/5=a

acceleration a=3.5 m/s^2

(c) ans

now we find the tension in the string

the tension in the string =M1a

=2*3.5=7 N

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