The lines in the figure below show the equipotential contours in the plane of th

Question

The lines in the figure below show the equipotential contours in the plane of three point charges, Q1, Q2, and Q3. Note that these are point charges (one is not bigger in size than the others; they're points). That means that the potential goes to infinity as you approach them. We've cut off the contours at plus and minus 7kV. The white space is where the potential is greater or less than that. The values of the equipotential lines are in kV, and we labeled the +1, 0, and -1 kV contours. The positions of the charges are also labeled.

Explanation / Answer

By the potential coutour we can say that Q1 and Q2 are negative charges and Q3 is positive

1. False. proton being positive will move towards more negative potential, hence towards Q2

2. True. As the potential gradient changes fasest close to Q2

3. True. As the potential contours surrounding it are negative

4. True. E is rate of change of V with respect to distance. At h the rate is non-zero so E is nonzero

5. True. The rate of change of V with respect to distance is more at g than a. So E is more at g than a.

6. True. As its field is spread the most

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