A.) Suppose we hook up a battery with a voltage of 3.85 V in a simple circuit wi

Question

A.) Suppose we hook up a battery with a voltage of 3.85 V in a simple circuit with a light bulb that has a resistance of 14.3 . Use Ohm’s Law to find the current flowing through the light bulb.

B.) We can turn the problem around as well. Again, hook up a simple circuit with a battery and a bulb. In this case we measure a current of 0.220 A flowing through the bulb which has a resistance of 17.8 . What is the voltage being applied to the bulb?

C.) To measure the resistance of a bulb, you can apply a voltage to the bulb and measure the current through the bulb. Suppose you hook the bulb up to a 6.90 V voltage source and measure a current of 0.300 A flowing through the bulb. What is the resistance of the bulb? (enter ohms for the units. Do not try to enter ).

D.) If a bulb of resistance 43.0 is connected to a 4.60-V voltage source, what is the power produced by the bulb?

Explanation / Answer

here,

A)

voltage of battery , V = 3.85 V

resistance of the bulb , r = 14.3 ohm

let the current flowing through bulb be I

using ohm's law

V = I * r

3.85 = I * 14.3

I = 0.27 A

the current flowing through the bulb is 0.27 A

B)

let the voltage of battery be V

resistance of the bulb , r = 17.8 ohm

the current flowing through bulb , I = 0.22 A

using ohm's law

V = I * r

V = 0.22 * 17.8

V = 3.92 V

the voltage of battery is 3.92 ohm

C)

resistance of the bulb , r = V/I

r = 6.9/0.3

r = 23 ohm

the resistance of the bulb is 23 ohm

D)

power , P = V^2 /r

P = 4.6^2 /43

P = 0.49 W

the power produced by the bulb is 0.49 W

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