PLEASE ANSWER ALL PARTS, THANK YOU! (20%) Problem 1: Unpolarized light of intens

Question

PLEASE ANSWER ALL PARTS, THANK YOU!

(20%) Problem 1: Unpolarized light of intensity I0 = 950 W/m^2 is incident upon two polarizers. After passing through both polarizers the intensity is I2 = 260 V/m^2. Randomized Variables I0 = 950 W/m^2 I2 = 260 W/m^2 Part (a) What is the intensity of the light after it passes through the first polarizer in W/m^2? Part (b) Write an equation for the angle between the polarizers in terms of the initial (I0) and final (I2) intensities. Part (c) Find the angle between the polarizers in degrees.

Explanation / Answer

given,

Io = 950 W/m^2

I2 = 260 W/m^2

after passing through first polarizer its intensity will become = Io / 2

so,

intensity after passing through first polarizer = 950 / 2

intensity after passing through first polarizer I1 = 475 W/m^2

let the angle between first and second polarizer be theta then,

I2 = (Io / 2) * cos^2(theta)

theta = arccos(sqrt(2 * I2 / Io))

theta = arccos(sqrt(2 * 260 / 950))

theta = 42.28 degree

angle between polarizers = 42.28 degree

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