Use the worked example above to help you solve this problem. A light ray of wave

Question

Use the worked example above to help you solve this problem. A light ray of wavelength 589 nm (produced by a sodium lamp) traveling through air is incident on smooth, flat slab of crown glass at an angle 1 of 32° to the normal, as sketched in the figure.

(a) Find the angle of refraction, 2.

(b) At what angle 3 does the ray leave the glass as it re-enters the air?

(c) How does the answer for the 3 change if the ray enters water below the slab instead of the air?

Suppose a light ray in air (n = 1.00) enters a cube of material (n = 2.50) at a 50.0° angle with respect to the normal and then exits the bottom of the cube into water (n = 1.33). At what angle to the normal does the ray leave the slab?

Explanation / Answer

Here ,

theta1= 32 degree

refractive index of crown glass , n2 = 1.54

a) using snell's law

n1 * sin(theta1) = n2 * sin(theta2)

1 * sin(32) = 1.54 * sin(theta2)

solving for theta2

theta2 = 20.12 degree

the angle of refraction is 20.12 degree

b)

Now, for the ray to reenter the glass

n2 * sin(theta2) = n1 * sin(theta3)

1.54 * sin(20.12) = 1 * sin(theta3)

theta3 = 32

the angle theta3 is 32 degree

c)

for the ray to enter water

using snell's law

n2 * sin(theta2) = n1 * sin(theta3)

1.54 * sin(20.12) = 1.33 * sin(theta3)

theta3 = 23.45 degree

the angle theta3 for glass water interface is 23.45 degree

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