can you please solve this with steps 2. A 10 grams bullet moving directly upward

Question

can you please solve this with steps

2. A 10 grams bullet moving directly upward strikes with a speed of 1000 m/s and passes through the center of mass of a 5 kg block initially at rest. The bullet emerges from the block moving directly upwards at 400 m/s. 2A (9 points) Calculate the vector linear momentum of the bullet right before the strike. Calculate the vector linear momentum of the bullet right after it emerges from the block. Calculate the change in the linear momentum of the bullet due to its collision with the S kg block. 2B (12 points) Calculate the vector velocity of the block right after its collision with the bullet. 2C (12 points) After the collision, to what height does the block then rise above its initial position?

Explanation / Answer

2A)
The vector linear momentum of the bullet before the strike, pi = m*vi j

= 0.01*1000 j

= 10 kg.m/s j

The vector linear momentum of the bullet after the strike, pf = m*vf j

= 0.01*400 j

= 4 kg.m/s j

chnage in momentum of the bullet = pf - pi

= 4 - 10

= -6 kg.m/s j

2B) gain in momentum of the block = -loss in momenumt of the bullet

M*v = -(-6)

5*v = 6

v = 6/5

= 1.2 m/s j
2C)

h = v^2/(2*g)

= 1.2^2/(2*9.8)

= 0.0734 m or 7.34 cm

Note: here j is unit vector along +y axis

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