1. A moving car rear ends a parked car. The parked car moves off at an angle of
ID: 1395641 • Letter: 1
Question
1. A moving car rear ends a parked car. The parked car moves off at an angle of 35 degrees
above the horizon. The rear car ricochets off at an angle of 35 degrees below the horizon. Both
cars have the same mass. If the moving car was moving 10 m/s and has a mass of 1000 kg.
FInd the following:
a. What is the initial momentum of the entire system?
b. What is the momentum of the entire system after the collision?
c. What is the final velocity of each car?
This is from my practive test so please show all work! I will be given one just like this on the test and need to know how to do it.
Explanation / Answer
a)Momentum = MV
Given
M1=M2=1000 kg
U1 = 10 m/s
U2 = 0 m/s
Initial Momentum of entire system = M1*U1 +M2*U2 = 1000*10 + 1000*0 = 10000 kg m/s
b) By principle of consevation of momentum
Initial Momentum = Final Momentum = 10000 kg m/s
c)We have to divide the momentums in x,y directions and Equate them for Conservation
In Y Direction
Intial Momentum = M1*U1 + M2U2 =0
Up Positive
after Collision in Y Direction = M1*(V1*sin((180+35)) + M2*(V2cos(35))
M1*(V1*sin((180+35)) + M2*(V2sin(35)) = 0
V1 = -V2
In X Direction Intial Momentum = M1*U1 =10000
To Right let it Be Positive
after Collision in X Direction = M1*(V1*cos((180+35)) + M2*(V2cos(35))
Equating
M1*(V1*cos((180+35)) + M2*(V2cos(35)) = M1*U1
2*V2*Cos 35 = 10 m/s
V2 = V1 = 6.1 m/s in magnitude
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