1. A metropolitan bus system sampler\'s rider counts on one of its express commu

Question

1. A metropolitan bus system sampler's rider counts on one of its express commuter routes for a week. Use the following data to establish whether ridership is evenly balanced by day of the week. Let =0.05. Monday Tuesday | Wednesday | Thursda Friday 21 57 Rider Count 1034 a) Is the 2 value significant at 5% level of significant? write the conclusion for this question b) Explain the major difference between 2 and ANOVA in terms of type of data (no calculation required) 2. Answer the following questions: a) lfr2=0.95, n=11 and the (v-5P=100, what iss: ors,,? Ifr -1, then s; in (45a) can be shown to have what type of relationship with SST and SSR? What relationship exists between j and Y where -1? What relationship exists between and Y where ?-0? b) e) d) e) Given the following information: = 0.95, n = 10 and k-2 what is the t-value for bi? t) In (e), you calculated t-value at the 0.05 level of significance; what statistical decision can you make about bi?

Explanation / Answer

1:

a)

Total observed ferqeuncies are: 10+34+21+57+44 = 166

If ridership is evenly balanced by the day os week then expected ferqeuncy for each day will be

E = 166 / 5 = 33.2

Following is the result of chi square test generated by excel:

Since p-value is less than 0.05 so chi square value is not signifcant at 5% level of signficance.

b)

Here we have counts for five categories. That is we have categorical data so we used chi square test instead of ANOVA.

Goodness of Fit Test observed expected O - E (O - E)² / E % of chisq 10 33.200 -23.200 16.212 39.26 34 33.200 0.800 0.019 0.05 21 33.200 -12.200 4.483 10.86 57 33.200 23.800 17.061 41.32 44 33.200 10.800 3.513 8.51 166 166.000 0.000 41.289 100.00 41.29 chi-square 4 df 2.34E-08 p-value

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