A pellet gun fires ten 2 g pellets per second with a speed of 500 m/s. The pelle

Question

A pellet gun fires ten 2 g pellets per second with a speed of 500 m/s. The pellets are stopped by a rigid wall.

a. What is the magnitude of the momentum of each pellet?

b. What is the kinetic energy of each pellet?

c. What is the magnitude of the average force on the wall from the stream of pellets?

d. If each pellet is in contact with the wall for seconds, what is the magnitude of the average force on the wall from each pellet during contact?

e. Why is the magnitude of the average force on the wall from each pellet during contact calculated in part d, so different from the magnitude of the average force on the wall from the stream of pellets calculated in part c.

Explanation / Answer

The momentum of each pellet is 2.9g*540 m/s=.002*500=1.566 kg m/s

F[avg]=p/t=(1.566kg m/s per pellet * 10 pellets)/1 second=15.66 N

F[avg]=(1.566 kg m/s )/.0008=1957.5 N

There is a lot of time in between pellets when no force is exerted on the wall

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