A pellet gun fires ten 2.0 g pellets per second with a speed of 500 m/s. The pel

Question

A pellet gun fires ten 2.0 g pellets per second with a speed of 500 m/s. The pellets are stopped by a rigid wall. What are? (a) The magnitude of the momentum of each pellet, (b) The kinetic energy of each pellet, and (c) The magnitude of the average force on the wall from the stream of pellets? (d) If each pellet is in contact with the wall for 0.60 ms, what is the magnitude of the average force on the wall from each pellet during contact? (e) Why is this average force so different from the average force calculated in (c)?

Explanation / Answer

a)

P=m*V =(2.8*10^-3)*480

P=1.344 Kg-m/s

b)

KE=(1/2)mV^2 =(1/2)*(2.8*10^-3)*480^2

KE=322.56 J

c)

F=nmV/t =10*(2.8*10^-3)*480/1

F=13.44 N

d)

F=-P/t =-1.344/0.7*10^-3

F=-1920 N

Most of the time ,no bullet is in contanct with the wall ,average is much smaller

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