FULL SCREEN PRINTER VERSION . BACK NEXT Your answer is partially correct. Try ag
ID: 1393300 • Letter: F
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FULL SCREEN PRINTER VERSION . BACK NEXT Your answer is partially correct. Try again. each has the same linear speed. However, one wheel is is sliding on a frictionless surface without rolling. Each wheel then encounters an incline plane. One continues to Two identical wheels are moving on horizontal surfaces. The center of mass of rolling, while the other is sliding on a frictionless surface without rolling roll up the incline, while the other continues to sl slows them down. Each wheel is a disk of mass 2.42 kg. On the horizontal surfaces the center of mass of ide up. Eventually they come to a momentary halt, because the gravitational force each wheel moves with a linear speed of 6.90 m/s. (a).(b) What is the total kinetic energy of each wheel? (c). (d) Determine the maximum height re y of each wheel? (c). (d) Determine the maximum height reached by each wheel as it moves up the incline 57 1 (a) KE.. 86.4 (b) KE 2.4 (c) hr m: 3.64 Click if you would like to Show Work for this question: Open Show Work GO TUTORIAL LINK TO TEXT Question Attempts: 2 of 5 used SAVE FOR LATERSUBMIT ANSWER SUBMIT ANSWERExplanation / Answer
a) Kinetic enrgy of rolling whell, KEr = 0.5*m*v^2 + 0.5*I*w^2
= 0.5*m*v^2 + 0.5*0.5*m*R^2*w^2
= 0.5*m*v^2 + 0.25*m*v^2
= 0.75*m*v^2
= 0.75*2.42*6.9^2
= 86.4 J<<<<<<<<----------Answwer
b) Kinetic enrgy of slipping whell, KEs = 0.5*m*v^2
= 0.5*2.42*6.9^2
= 57.6 J <<<<<<<<----------Answwer
c)Apply energy conservation
initial keintic energy = final potential enrgy
KEr = m*g*hr
==> hr = KEr/(m*g)
= 86.4/(2.42*9.8)
= 3.64 m <<<<<<<<----------Answwer
d)Apply energy conservation
initial keintic energy = final potential enrgy
KEs = m*g*hs
==> hs = KEs/(m*g)
= 57.6/(2.42*9.8)
= 2.43 m <<<<<<<<----------Answwer
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