FREEZING POINT DEPRESSION LAB Explain how the following errors would affect the
ID: 807840 • Letter: F
Question
FREEZING POINT DEPRESSION LAB
Explain how the following errors would affect the calulcated molecular weight of your unkowns if you were not aware they had occured.
a) Some solvent is lost by evaporation from the unkown solution.
b) THermometer reads 1 C too low along its entire range
c) part of the unkown solute fails to dissolve.
d) If in the process of dissolving in a particular solvent a solute dimerizes, what effect will this have on the calculated molecular weight?
e) Explain what effect in any impourities in the solvent would have on the calculated molecular weight provided they dont interact with your solute.
Explanation / Answer
1) for calculating freezing point depression , MOLALITY is to be calculated after proper mixing of solute in solvent, so given if solvent is lost then molality in given volume of solvent will be different . we may get an eror.
2) for finding out freezing point , we actually focuss on delta T ...ie difference in the temperature...so if the thermometer has an error...we still gets the same "delta T" value
3) same reason i gave for the 1st answer..MOLALITY is all about amount of solute into amount of solvent.. given solute doesnt dissolve...we will get the result according to the amount that has been dissolved ie lesser solute...so calculations would have an error
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