Two long, parallel conductors, separated by 13.0 cm, carry currents in the same
ID: 1391301 • Letter: T
Question
Two long, parallel conductors, separated by 13.0 cm, carry currents in the same direction. The first wire carries a current I1 = 6.00 A, and the second carries I2 = 8.00 A. (See figure below. Assume the conductors lie in the plane of the page.)
(a) What is the magnetic field created by I1 at the location of I2?
in the +x direction
in the -x direction
in the +y direction
in the -y direction
in the +z direction
in the -z direction
(b) What is the force per unit length exerted by I1 on I2?
in the +x direction
in the -x direction
in the +y direction
in the -y direction
in the +z direction
in the -z direction
(c) What is the magnetic field created by I2 at the location of I1?
in the +x direction
in the -x direction
in the +y direction
in the -y direction
in the +z direction
in the -z direction
(d) What is the force per length exerted by I2 on I1?
in the +x direction
in the -x direction
in the +y direction
in the -y direction
in the +z direction
in the -z direction
Explanation / Answer
a)
magnetic field due to I1 is
B1 = u0 * I1/(2*pi*d)
B1 = u0 * 6 /(2 *pi*0.13)
B1 = 9.23 *10^-6 T in +ve Z - direction
b)
force on I2 by I1 ,
F = B*I2
F = 9.23 *10^-6 * 8
F = 7.4 *10^-5 N/m
the force on I2 is 7.4 *10^-5 N/m in +y - direction
c)
Now, field due to I2 ,
B2 = u0 * I2/(2*pi*d)
B2 = u0 * 8 /(2 *pi*0.13)
B2 = 1.231 *10^-5 T
field due to wire 2 is 1.231 *10^-5 T in -ve Z - direction
d)
Using newton's third law ,
F = 7.4 *10^-5 N/m
the force on I2 is 7.4 *10^-5 N/m in - y - direction
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.