Two long, parallel conductors, separated by 13.0 cm, carry currents in the same

Question

Two long, parallel conductors, separated by 13.0 cm, carry currents in the same direction. The first wire carries a current I1 = 6.00 A, and the second carries I2 = 8.00 A. (See figure below. Assume the conductors lie in the plane of the page.) (a) What is the magnetic field created by I1 at the location of I2? What is the equation giving the magnetic field of a long, straight, current-carrying wire? T (b) What is the force per unit length exerted by I1 on I2? (c) What is the magnetic field created by I2 at the location of I1? (d) What is the force per length exerted by I2 on I1?

Explanation / Answer

Given that the current is I1 = 5.00 A andI2 = 8.00 A     The separation between the wires is d =10.0 cm = 0.1 m --------------------------------------------------------------------------------- (a) the magnitude of the magnetic field created byI1 at the location ofI2                     B1 = 0*I1 / 2d                           =( 4*10-7 T.m/A)*I1 / 2d                          = 10*10^-6 T
                         = 10T (b) the force per unit length exerted onI2 by I1                  F / L = 0*I1*I2 / 2d                           = 80*10^-6 N/m
                          = 80 N/m
(c) the magnitude of the magnetic field created byI2 at the location of I1                     B1 = 0*I2 / 2d                           =( 4*10-7 T.m/A)*I1 / 2d                          = 16*10^-6 T
                         = 16 T (d)   the force per unit length exerted onI1 by I2                  F / L = 0*I1*I2 / 2d                           = 80*10^-6 N/m
                         = 80 N/m
      
                    B1 = 0*I2 / 2d                           =( 4*10-7 T.m/A)*I1 / 2d                          = 16*10^-6 T
                         = 16 T                  F / L = 0*I1*I2 / 2d                           = 80*10^-6 N/m
                         = 80 N/m

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.