A 1000- kg car collides with a 1500- kg car that was initially at rest at the or

Question

A 1000- kg car collides with a 1500- kg car that was initially at rest at the origin of an x-y coordinate system. After the collision, the lighter car moves at 10.0 km/h in a direction of 30 o with respect to the positive x axis. The heavier car moves at 13 km/h at -44 o with respect to the positive x axis.
What was the initial speed of the lighter car (in km/h)?

What was the initial direction (as measured counterclockwise from the x-axis)?

A 1000- kg car collides with a 1500- kg car that was initially at rest at the origin of an x-y coordinate system. After the collision, the lighter car moves at 10.0 km/h in a direction of 30 o with respect to the positive x axis. The heavier car moves at 13 km/h at -44 o with respect to the positive x axis. What was the initial speed of the lighter car (in km/h)? What was the initial direction (as measured counterclockwise from the x-axis)? Car Collision in 2D

Explanation / Answer

According to law of conservation of momentum along x-axis is

m1 u1 = m1 u1 cos 30 + m2 u2 cos44

= (1000 kg ) ( 10 *1000/3600 m/s) cos 30 + ( 1500 kg ) ( 13*1000 /3600 m/s) (cos 44)

= 6302.05

u1 = 6302.5 / m1

= 6302.5 / 1000 kg

= 6.3 m/s

The initial direction of lighter car is along x-axis.

= 22.68 km/h

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.