Suppose a 2.50 N force can rupture an eardrum having an area of 1.29 cm2. (a) Ca

Question

Suppose a 2.50 N force can rupture an eardrum having an area of 1.29 cm2.

(a) Calculate the maximum tolerable gauge pressure inside the eardrum (in the middle ear) in N/m2. (Pressures in the middle ear may rise when an infection causes a fluid buildup. Use 13.6 ? 103 kg/m3 as the density of mercury.)

________N/m2

Convert this value to mm Hg.

__________mm Hg

(b) At what depth in fresh water would this person's eardrum rupture, assuming the gauge pressure in the middle ear is zero? __________m

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Explanation / Answer

Part A)

Pressure = F/A

P = (2.5)/(1.29 X 10-4)

P = 1.94 X 104 Pa

In mm of Hg, that is...

(1.94 X 104) X (7.501 X 10-3 mm Hg per Pa) = 145.4 mm Hg

Part B)

P = pgh

1.94 X 104 = 1000(9.8)(h)

h = 1.98 m

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