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Two long, parallel transmission lines, 41.5 cm apart, carry 27.0-A and 79.0-A cu

ID: 1374256 • Letter: T

Question

Two long, parallel transmission lines, 41.5 cm apart, carry 27.0-A and 79.0-A currents. (a) Find all locations where the net magnetic field of the two wires is zero ?f the currents are in the same direction. B tot = 0 along a line m from the wire carrying 79.0 A and m from the wire carrying current 27.0 A. (b) Find all locations where the net magnetic field of the two wires is zero if the currents are ?n the opposite direction. B tot = 0 along a line m from the wire carrying 27.0 A and m from the wire carrying current 79.0 A.

Explanation / Answer

Note that the magnitude of the B field due to a long wire is

B = uo I / [2 pi r]

where r is the distance from the wire.

If they have current in the same direction, then

Bnet = 0 = uo (27.0 A) / [2 pi d] - uo [79.0 A] / [2 pi (0.415 m - d)]

where d = the distance from the 27.0 A wire.

Thus, solving for d,

d = 0.106 m

Thus:

Btot = 0 along a line 0.309 m from the wire carrying 79.0 A and 0.106 m from the wire carrying 27.0 A.   [ANSWER, PART A]

**********************

Note that the magnitude of the B field due to a long wire is

B = uo I / [2 pi r]

where r is the distance from the wire.

If they have current in the opposite direction, then

Bnet = 0 = uo (27.0 A) / [2 pi d] - uo [79.0 A] / [2 pi (0.415 m + d)]

where d = the distance from the 27.0 A wire.

Thus, solving for d,

d = 0.2155 m

Thus:

Btot = 0 along a line 0.2155 m from the wire carrying 27.0 A and 0.6305 m from the wire carrying 79.0 A.   [ANSWER, PART B]

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