A 32.0 omega resistor? A g) What is the current through the second resistor? A o

Question

A 32.0 omega resistor? A g) What is the current through the second resistor? A omega resistor? V e) What is the voltage drop across the second resistor V f) What is the current through the 32.0 omega b) What is the current out of the battery? A c) What is the voltage out of the battery? V d)What is the voltage drop across the 32.0 omega b) What is the equivalent resistance across the combination of the two resistors? omega resistor and a second resistor are connected in parallel across a 25.0 V battery. A current of 2.0 A flows through the second resistor. Analyze the circuit to determine the values described below. Hint, use the grid method to solve for unknowns and then fill then in values below. (They will not necessarily be in order.) a) What is the resistance of the second resistor?

Explanation / Answer

Given that,

R1 = 32 Ohm ; R2= ? ; V = 25 V ; I2(current through R2) = 2 A

the resistors are connected in parallel throgh 25 Volts, so voltage drop is going to be the same across both the resistors.

So, V1 = V2 = 25 Volts

(a)

Now we know that, V = IR so R = V / I

R2 = V2 / I2 = 25 / 2 = 12.5 Ohm

R2 = 12.5 Ohm

(b) R(eq) will be given by

1/R(eq) = 1/R1 + 1/ R2 = 1/32 + 1/12.5 = 44.5 / 400

R(eq) = 400 / 44.5 = 8.99 Ohm

(c)we know that,

V = IR so I = V/R = 25/8.99 = 2.78

Hence, Current through the battery I = 2.78 Ampere

Voltage out of battery is 25 V

(d) Volateg drop across R1 is 25 V as its a parallel combination.

(e) Volateg drop across R2 is 25 V as its a parallel combination.

(f) current through R1 = 32 ohm will be

I1 = V2 / R1 = 25/32 = 0.781 Ampere

(g)Current through R2 = 12.5 Ohm

I2 =25 / 12.5 = 2 Ampere

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