Green Arrow shoots an arrow at a speed of 98 m/s that is charged to 5 Coulombs a

Question

Green Arrow shoots an arrow at a speed of 98 m/s that is charged to 5 Coulombs and has a mass of 18 grams through a potential difference towards his enemy Deathstroke. The charged arrow is shot from the origin (x = 0 m) where the potential is 0 V, and the potential difference 150 m (x = 150 m) away is 150 V. Assume the potential difference increases linearly (as it does between capacitor plates.)

Solve to find the electric potential that stops the arrow that was fired?

what is the distance that the arrow stops?

Explanation / Answer

First, from conservation of energy...

qV = .5mv2

(5)(V) = .5(.018)(98)2

V = 17.3 Volts

For the distance, since it increases linearly and every meter is 1 volt, that means...

17.3 Volts will need 17.3 meters

150/

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