Green Arrow shoots an arrow at a speed of 98 m/s that is charged to 5 Coulombs a

Question

Green Arrow shoots an arrow at a speed of 98 m/s that is charged to 5 Coulombs and has a mass of 18 grams through a potential difference towards his enemy Deathstroke. The charged arrow is shot from the origin (x = 0 m) where the potential is 0 V, and the potential difference 150 m (x = 150 m) away is 150 V. Assume the potential difference increases linearly (as it does between capacitor plates.)

A) Solve to find the electric potential that stops the arrow that was fired.

B) Translate the electric potential that stops the arrow into the distance from the starting location that the charged arrow is stoped

C) Deathstroke (Green Arrow's enemy) is 15 m away from where Green Arrow fired the charged arrow. Does the charged arrow hit the villain, or does the electric potential stop it in time to allow Deathstroke to escape?

Explanation / Answer

Solution: -the potential is increasing linearly. it clearly means if at x= 0 potential is 0 V

and potential difference at 150 m is 150 V. then of course at any particular x metres, the potential should be x V.

So, according to work energy theorem the positively charged arrow is going from lower to higher potential and so the kinetic energy will decrease and eventually be zero

so,

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