An oscillator circuit is important to many applications. A simple oscillator cir

Question

An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in the figure (Figure 1). Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value V_on, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value V_off, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between V_off, when it starts charging, and V_on, when the light comes on to discharge it. What is the oscillation period T? A neon gas tube has V_on = 50.0 V and V_off = 10.0 V . What resistor value should you choose to go with a 40.0 mu F capacitor and a 110 V battery to make a 10.0 Hz oscillator?

Explanation / Answer

E=110V , Von=50V, Voff = 10V , C=40*10-6 F , f= 10Hz

T=1/f= 1/10Hz= 0.1s

Use equation,

T= RCln[(E-Voff)/(E-Von)]

Plugging values,

0.1=R*(40*10-6)ln[(110-10)/(110-50)]    => R= 4894.04 ohm

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