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Based off of the problem listed below, I need to create a problem that relates w

ID: 1363209 • Letter: B

Question

Based off of the problem listed below, I need to create a problem that relates water and a metal (preferably copper or iron I can't use aluminum because that's what my professor used in this example) and I need to make a problem like this, but converting it from ice to water. Any help would be greatly appreciated I am confused on how I can go about this.

A person puts 500 g of water in a freezer inside a 1500 g aluminum pot. Initially, the water and pot are at an equilibrium temperature of 20 degree Celsius. How much energy does the freezer need to remove from the ice/pot system to make ice at -10 degrees Celsius?

Explanation / Answer

Lets modify the problem to copper:
A person puts 500 g of water in a freezer inside a 1500 g copper pot. Initially, the water and pot are at an equilibrium temperature of 20 degree Celsius. How much energy does the freezer need to remove from the ice/pot system to make ice at -10 degrees Celsius?

Data needed :
Specific heat caapcity of water, Cw: 4.186 J/goC
Specific heat caapcity of ice, Ci: 2.03 J/goC
Specific heat caapcity of copper, Cc: 0.386 J/goC
Laten heat of fusion of water: Lw: 334 J/g

Total Heat required = Heat required to take water from 20 oC to 0oC + heat required to freeze it + heat required to take ice from 0 oC to -10 oC + heat required to take copper from 20 oC to -10 oC
Total Heat required = mw*cw*(20-0) + mw*Lw + mw*Ci*(0-(-10)) + mc*Cc*(20-(-10))
=500*4.186*20 + 500*334 + 500*2.04*10 + 1500*0.386*30
=236430 J
Answer: 236430 J or 236.4 KJ

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