Baseball player A bunts the ball by hitting it in such a way that it acquires an

Question

Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of 1.9 m/s parallel to the ground. Upon contact with the bat the ball is 1.2 m above the ground. Player B wishes to duplicate this bunt, in so far as he also wants to give the ball a velocity parallel to the ground and have his ball travel the same horizontal distance as player A's ball does. However, player B hits the ball when it is 1.5 m above the ground. What is the magnitude of the initial velocity that player B's ball must be given?

Explanation / Answer

s1 = v1 * t1  where v1 is the horizontal speed of the ball ands1 the distance traveled

s2 = v2 *t2    and s1 =s2         so v2 = v1 * t1 /t2

The ball falls a distance h = 1/2 * g *t^2     so t = ?(2 * g * h) in timet

Then v2 = v1 * ?(h1 /h2) = 1.9 m/s * ?(1.2 / 1.5) = 1.7m/s

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