Baseball home run. A slugger hits a ball. The speed of the ball as it leaves the

Question

Baseball home run. A slugger hits a ball. The speed of the ball as it leaves the bat is v0 = 100 mi/hr = 147 ft/s. Suppose the direction of the initial velocity is 45 degrees above the horizontal, and the initial height is 3 ft. The acceleration due to gravity is 32 ft/s^2. (A) When precisely will the ball hit the ground? (B) Where precisely will the ball hit the ground? (C) We have neglected air resistance. Is that a good approximation? Justify your answer.

Explanation / Answer

R = u^2 sin 2@ /g => put values to get the answer Refer question 4: http://www.pa.msu.edu/~stump/champ/mech2f01.pdf

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