a seesaw of length 2m, normally with the pivot (point of support) located halfwa
ID: 1357894 • Letter: A
Question
a seesaw of length 2m, normally with the pivot (point of support) located halfway between the two seats, can be shifted make the pivot closer one seat than the other. this is to make it easier for riders of greatly unequal weight to balance. suppose there are two riders of unequal masses mL= 20 kg and mR= 30 kg in the left and right seats of the seesaw, respectively. they want to adjust the seesaw so that they can perfectly balance. what distance d between the left-hand rider and the pivot would make this happen?
Explanation / Answer
torque =force x distance
net torque at pivot =0
20 x 9.8 x d = 30 x 9.8 x( 2-d)
d= 60/50 =6/5 =1.2m
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