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a sample of gas occupies a value of 55.9 ml In this virtual lab you will use cof

ID: 889103 • Letter: A

Question

a sample of gas occupies a value of 55.9 ml In this virtual lab you will use coffee cup calorimetry to determine the specific heat,c of a metal /2015 11:55 PM A 12.8/15 9/24/2015 01:52 PM Grac Print Calculator -J) Periodic Table n3 of 14in Mapd g leaming A sample of gas occupies a volume of 55.9 mL. As it expands, it does 116.7 J of work on its surroundings at a constant pressure of 783 torr. What is the final volume of the gas? Number 169.20 mL O Previous Give Up & View Satulion O Check Answer 0 Next Exit- Hint

Explanation / Answer

1. let us consider isothermal expansion of gas,

Wirr = -PDV

P = 783 torr = 1.030 atm

DV = v2-v1

v2 = final volume of gas = ?

v1 = initial volume of gas = 55.9 ml

work done on surroundings = - work done by the gas.

wirr = - 116.7 joule = - 1.15 L.atm ( 1 L.atm = 101.2 joule)

- 1.15 = - 1.030 *(V2-55.9)

V2 = 57.2 ml = final volume of gas

2.

heat lost by the metal = heat gained by the water

heat gained by the water qwater = mass of water*Specific heat of water*DT

     = 130*4.184*(23-20)

     = 1631.76 joule.

therefore,

heat lost by the metal(qmetal) = 1631.76 joule.

mass of metal = 45 grams
                    
DT = Ti-Tf

Tf = 23 C , Ti = highest temperature of metal = 84 C

DT = 84-23 = 61 C

qmetal = mass of metal * Specific heat of metal * DT

Specific heat of metal = qmetal / mmetal*DT

               = 1631.76/(45*61)

Specific heat of metal = 0.594 j/g.C

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