1.Light of wavelength 610 nm illuminates a diffraction grating. The second-order

Question

1.Light of wavelength 610 nm illuminates a diffraction grating. The second-order maximum is at angle 41.5 .

A.How many lines per millimeter does this grating have?

2.Two narrow slits 90 m apart are illuminated with light of wavelength 560 nm .

A.What is the angle of the m=3 bright fringe in radians?

B.What is the angle in degrees?

3.Light of 550 nm wavelength illuminates a double slit. The intensity pattern shown in the figure(Figure 1) is seen on a screen 2.1 m behind the slits.

A.What is the spacing (in mm) between the slits?

4.A 4.8-cm-wide diffraction grating has 2100 slits. It is illuminated by light of wavelength 540 nm

a.What is the angle (in degrees) of the first diffraction order?

b.What is the angle (in degrees) of the second diffraction order?

5.A helium-neon laser (=633nm) illuminates a diffraction grating. The distance between the twom=1 bright fringes is 32 cm on a screen 2.3 mbehind the grating.

a.What is the spacing between slits of the grating?

Explanation / Answer

Here ,

1)

wavelength = 610 nm

theta = 41.5 degree

for the second order maximum

d * sin(theta) = 2 * wavelength

d* sin(41.5) = 2 * 610*10^-9

d = 1.841 *10^-6 m = 1.841 *10^-3 mm

lines per mm = 1/(1.841 *10^-3)

lines per mm = 543.13

the lines per mm is 543.13

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