A horizontal spring attached to a wall has a force constant of k = 880 N/m. A bl

Question

A horizontal spring attached to a wall has a force constant of k = 880 N/m. A block of mass m = 1.40 kg is attached to the spring and rests on a horizontal, frictionless surface as in the figure below. (a)The block is pulled to a position x = 6.20 cm from equilibrium and released. Find the elastic potential energy stored in the spring when the block is 6.20cm from equilibrium and when the block passes through equilibrium. (b) Find the speed of the block as it passes through the equilibrium point. b/s (c) What is the speed of the block when it is at a position 42 = 3.1 cm? m/s (d) Why isn?t the answer to part (c) half the answer to part (b)?

Explanation / Answer

mass m=1.4 kg

spring constant k=880 N/m

a)

at x=6.2cm

elastic potential energy U=1/2*k*x^2

U=1/2*880*(6.2*10^-2)^2

U=1.69 J

at x=0 :elastic potential energy U=0

b)

at eqilibrium position,

Total energy =K.E=U

1/2*m*v1^2=1.69

1/2*1.4*v1^2=1.69

v1=1.55 m/sec

c)

at x=3.1 cm

T.E=K.E+U

1.69=1/2*m*v2^2+1/2*k*x^2

1.69=1/2*1.4*v2^2+1/2*880*(3.1*10^-2)^2

===> v2=1.34 m/sec

d)

here,

v2 is not equals to v1/2

because,

K.E and U enrgy is proportiona to v^2 and x^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.