A 31.0-kg block is resting on a flat horizontal table. On top of this block is r

Question

A 31.0-kg block is resting on a flat horizontal table. On top of this block is resting a 10.0-kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is 325 N/m. The coefficient of kinetic friction between the lower block and the table is 0.430, and the coefficient of static friction between the two blocks is 0.740. A horizontal force is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed. Determine the amount by which the spring is compressed at the point where the upper block begins to slip on the lower block.

Explanation / Answer

Constant speed ---> a = 0 . Then:
a).k x = mu *m1 g ---> x = mu*m1 g/k = 0.740*10*9.8/325= 0.223m

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