Two ice pucks (one orange and one blue) of equal mass are involved in a perfectl

Question

Two ice pucks (one orange and one blue) of equal mass are involved in a perfectly elastic glancing collision as shown in the figure below. The orange puck is initially moving to the right at voi = 4.10 m/s, strikes the initially stationary blue puck, and moves off in a direction that makes an angle of = 38.0° with the horizontal axis while the blue puck makes an angle of = 52.0° with this axis as in figure (b). Note that for an elastic collision of two equal masses, the separation angle + = 90.0°. Determine the speed of each puck after the collision.

Explanation / Answer

let mb = mo = m

voi = 4.1 m/s

vbi = 0

Let

vof and vbf are the final speeds of orange and blue pucks.

Apply conservation of momentum in y d-direction

0 + 0 = mo*vof*sin(38) - mb*vbf*sin(52)

vbf = vof*sin(38)/sin(52)

= 0.781*vof

Apply conservation of momentum in x-direction

mb*voi + 0 = mo*vof*cos(38) + mb*vbf*cos(52)

voi = vof*cos(38) + 0.781*vof*cos(52) (since vbf = 0.781*vof)

4.1 = 1.269*vof

==> vof = 4.1/1.269

= 3.23 m/s <<<<<<<<------------Answer

vbf = 0.781*3.23

= 2.52 m/s <<<<<<<<------------Answer

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