A stone is thrown with 75 degree angle to x axis with an initial speed of 10 m/s

Question

A stone is thrown with 75 degree angle to x axis with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's trajectory time from the top of the cliff to the bottom to be 5 s. How far the stone will land from the base of the cliff? A stone is thrown with 75 degree angle to x axis with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's trajectory time from the top of the cliff to the bottom to be 5 s. How far the stone will land from the base of the cliff? A stone is thrown with 75 degree angle to x axis with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's trajectory time from the top of the cliff to the bottom to be 5 s. How far the stone will land from the base of the cliff? A stone is thrown with 75 degree angle to x axis with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's trajectory time from the top of the cliff to the bottom to be 5 s. How far the stone will land from the base of the cliff?

Explanation / Answer

Here ,

theta = 75 degree

initial speed , u = 10 m/s

time , t = 5 s

Now , distance from the base of rock = u * cos(theta)* t

distance from the base of rock = 10 * cos(75) * 5

distance from the base of rock = 12.94 m

the distance from the base of rock is 12.94 m

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