How to solve this? problem 3 and 4 3. Figure below shows the common emitter npn

Question

How to solve this? problem 3 and 4

3. Figure below shows the common emitter npn transistor. (a) It has a base current of 8 and a collector current of 1.2 mA. Find the (b) It has an emitter current of 2.42 mA and a collector current of 2.4 mA. (c) It has a base current of 16 A and a factor of 80, what is the collector npn common emitter transistor factor, the 04 and the emitter current. what is the base current and the factor of the transistor? current and emitter current of the transistor? 4, A BJT has a base current of 250 A and emitter current of 15mA. Find the collector current gain and

Explanation / Answer

3.a) Ib = 8 uA
Ic = 1.2 mA
as Ic = beta*Ib
beta = Ic/Ib = 150

also , Ic/Ie = alpha , where Ie = (1+beta)Ib
alpha = Ic/Ie = beta / (1+beta) = 150/151 = 0.99337
Ie = (1+beta)Ib = 151*8 uA = 1.208 mA
----------------------
b) Ie = 2.42 mA, Ic = 2.4 mA
as, alpha = Ic/Ie = beta / (1+beta)
Ic/Ie = 2.4/2.42 = 0.992
beta / (1+beta) = 0.992
beta = 0.992/0.008 = 124
Ib = Ic/beta = 2.4 mA / 124 = 0.0194 mA
---------------------------
c) Ib = 16 uA , beta = 80 ,
Ic = beta *Ib = 1.28 mA
Ie = (1+beta)Ib = 1.296 mA
========================================
4. ) Ib = 250 uA , Ie = 15mA
as Ie = (1+beta)*Ib
15 x 10^-3 = (1+beta)250 x 10^-6
1+beta = 60
beta =59
collector current gain = alpha = beta / (1+beta) = 59/60 = 0.9833

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