A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m

Question

A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m high. Assume the coefficient of kinetic friction is 0.23. What is the actual mechanical advantage and incline plane efficiency?

Actual MA =  [Num]

Incline Efficiency =  [Num]%

A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m high. Assume the coefficient of kinetic friction is 0.23. What is the actual mechanical advantage and incline plane efficiency?

Actual MA =  [Num]

Incline Efficiency =  [Num]%

Explanation / Answer

here,

b = 6.1 m
p = 2.5 m
uk = 0.23
mass = 9 kg

h = sqrt(6.1^2 + 2.5^2)
h = 6.59

cosA = b/h = 6.1 / 6.59
CosA = 0.92
A = 23.07 degrees

Mechanical advantage for Inclined plane, is given as

MA = X / Y

Where,
X = Ratio of the force you have to apply for meeting the objective without using the tool.

Y = Force you have to apply for meeting your objective using the tool.
Hence

MA = 1 / sinA + ff
MA = 1 / (sin23.07 + uk*cos23.07 )
MA = 1 /(0.39+0.23*0.92)
MA = 1.662

actual mechanical advantage 1.662

Efficiency = Ideal mechanical advantage / actual mechanical advantgae

% = sinA/(1.662)
% = 0.39/1.662
% = 0.235 *100
% =23.5 percent

Incline Efficiency is 23.5 %

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