A ball gets firmly lodged between the plates of the largest capacitor (C L ). Wh
ID: 1333710 • Letter: A
Question
A ball gets firmly lodged between the plates of the largest capacitor (CL). When the ball is between the plates, the capacitor charges and acts like a dielectric with dielectric constant K and permittivity K. The capacitor is attached to a battery of voltage V and fully charges. What constant force (F) must I apply in order to remove the ball from the plates? Your answer should be in terms of CL V, L and K(or K) *Hint: what is the energy in the capacitor with and without the Dielectric? In order to change energy I have to do work.
Explanation / Answer
energy stored in the capacitor before dielectric is placed
U1 = 0.5*CL*V^2
energy stored after the dielectric is placed
on placing a dielectric the capacitance increases by k
U2 = 0.5*(k*CL)*V^2
work done is equal to change in energy
W = U2 - U1 = 0.5*CL*V^2*(k-1)
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.