Electric forces and Coulomb\'s law: PLEASE HELP...I keep getting this wrong! I d

Question

Electric forces and Coulomb's law:

PLEASE HELP...I keep getting this wrong! I dont know why!

PSS 20.1: Electric forces and Coulomb's law

Learning Goal:

To practice Problem-Solving Strategy 20.1 Electric forces and Coulomb's law.

Two charged particles, with charges q1=q and q2=4q, are located at a distance d=2cm apart on the x axis. A third charged particle, with charge q3=q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3.

Find the position of charge 3 when q = 1.0 nC .

Homework 3 PSS 20.1: Electric forces and Coulomb's law Resources « previous | 2 of 25 ne Part B PSS 20.1: Electric forces and Coulomb's law Suppose charge 3 is placed in between the other two charges, as shown below. Use this diagram to show the force vectors representing all the forces acting on charge 3. Draw each vector so that it has the correct orientation. Do not worry about magnitudes. Learning Goal To practice Problem-Solving Strategy 20.1 Electric forces and Coulomb's law Draw the vectors starting at the location of charge 3. The location and orientation of the vectors will be graded. The length of the vectors will not be graded Two charged particles, with charges q1 = q and g2 = 40 are located at a distance d = 2 cm apart on the x axis. A third charged particle, with charge q3 = q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3 add elementv vector sum delete element attributes reset ? help Find the position of charge 3 when q = 1.0 nC Note that you are given the magnitude of q, but the sign of the charge q is not specified. q can be positive or negative, so that the three charges (q1, 2, 3) are either all positive charges or all negative charges 91 93 lon3

Explanation / Answer

F1 = force by charge q1 is given as

F1 = k q1 q3 / r12 = (9 x 109) (q) (q) / d2                      eq-1

F2 = force by charge q2 is given as

F2 = k q2 q3 / r12 = (9 x 109) (4q) (q) / (0.02 - d)2                     Eq-2

equating the forces

F1 = F2

(9 x 109) (q) (q) / d2   = (9 x 109) (4q) (q) / (0.02 - d)2    

1/d2 = 4 / (0.02 - d)2  

d = 0.0067 m

d = 0.67 cm from charge q1 towards right

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