Force on a Crate Due in 20 hours, 34 minutes A crate weighing 541 N is being pul

Question

Force on a Crate

Due in 20 hours, 34 minutes

A crate weighing 541 N is being pulled across the floor. You pull up and to the right on a rope which is attached to the crate. You exert a force of 178 N at an angle ?=38.0° above the horizontal.

Consider the +x to be to right and +y to be upward. What is the horizontal(x) component of the force you exert on the crate?

Tries 0/10

What is the vertical(y) component of the force you exert on the crate?

Tries 0/10

Since you are pulling up a little bit on the crate, the floor doesn't have to support as much weight. When you are pulling up on the rope as described above, what is the upward force that the floor exerts on the crate. (Note: will it be bigger, smaller, or the same as the weight of the crate?)

Explanation / Answer

horizantal component = Fx = F*co38 = 178*cos38 = 140 N

vertical component = Fy = 178*sin38 = 109.6 N

in vertical

N + Fy = W

N = W - Fy

N = upward force is less than Weigh W

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