For/While Loop: Using either a for-loop or while-loop. identify how close two wo

Question

For/While Loop: Using either a for-loop or while-loop. identify how close two words are by incorporating a loop using the following algorithm: First determine whether or not the two words are the same length If the words are different lengths, then output the difference of the two lengths and exit. If the words are the same length, then step through the letters of each word using a for-loop and identify the number of characters that are mismatched. For example, the words bat and bag have 1 mismatch whereas bag and bag have 0 mismatches. Output the two words and the number of mismatches.

Explanation / Answer

#include<stdio.h>

void main() {

   char word1[50], word2[50];

   printf("Enter word 1: ");
   scanf("%s", word1);
   printf("Enter word 2: ");
   scanf("%s", word2);

   printf("Difference between word '%s' and word '%s' is %d",word1, word2, wordDiff(word1, word2));
}

int wordDiff(char *word1, char *word2) {
   int length1, length2, count = 0, i;
   for (length1 = 0; word1[length1]!=''; length1++); //calculate length
   for (length2 = 0; word2[length2]!=''; length2++); //calculate length
   if (length1 == length2){ //if lengths are equal
       for (i = 0; i<length1; i++) //for every letter of both words
           if (word1[i]!=word2[i]) //are equal
               count ++; //increase count
       return count; //and finally return count
   }
   if (length1 > length2) //this actullay calculate and returns the absolute value of length1 - length2
       return length1 - length2;
   return length2 - length1;
}

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