A 440g block of iron at 440 degrees Celsius is dropped into a calorimeter contai

Question

A 440g block of iron at 440 degrees Celsius is dropped into a calorimeter containing 60g of water at 30 degrees Celsius. How much steam is produced? The latent heat of vaporization of water is 22.6 x 10^5 J/kg. The average specific heat of iron over this temperature range is 560 J(kg/K) A 440g block of iron at 440 degrees Celsius is dropped into a calorimeter containing 60g of water at 30 degrees Celsius. How much steam is produced? The latent heat of vaporization of water is 22.6 x 10^5 J/kg. The average specific heat of iron over this temperature range is 560 J(kg/K)

Explanation / Answer

Here , heat lost by iron to come at 100 C

is Q = m*S*del T

Q = 440 * 0.560 * (440 - 100)

Q = 83766 J

Now , for taking the water to 100 C and converting it to heat

Q = 60 * 4.186 * (100 - 30) + m * 22.6*10^3

83766 =  60 * 4.186 * (100 - 30) + m * 22.6*10^3

solving for m

m = 2.93 gm

2.93 grams of steam will be produced

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