a) Without doing any simplification (or combination) identify the number of pair

Question

a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series.

b) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in parallel.

c) Find R12 the equivalent resistance of resistors R1, and R2.

d) Find R123 the equivalent resistance of resistors R1, R2, and R3.

e) Find R12345 the equivalent resistance of resistors R1, R2, R3, R4, and R5.

For the circuit shown, R1= R3 = R9 = R11 = 81.0 Ohms, the rest of the resistors are 162.0 Ohms. a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series. b) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in parallel. c) Find R12 the equivalent resistance of resistors R1, and R2. d) Find R123 the equivalent resistance of resistors R1, R2, and R3. e) Find R12345 the equivalent resistance of resistors R1, R2, R3, R4, and R5.

Explanation / Answer

a) 1 pair in series(R1 and R2)

b) 1 pair in parallel (R6 and R7)

c)R12 = R1 + R2 = 81 +162 = 243 ohm (ans)

d)R123 = R12 is parallel to R3

=> R123 = 243*81/(243+81) = 60.75 ohm (ans)

R123 is in series with R4

R1234 = 60.75 + 162 = 222.75

R1234 parallel to R5

e) R12345 = 222.75*162/(222.75+162) =93.7895 ohm (ans)

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