A copper wire has diameter 0.110mm and length 11.0cm . Its in a horizontal plane

Question

A copper wire has diameter 0.110mm and length 11.0cm . Its in a horizontal plane and carries a current of 2.50A . The density of copper is 8920 kg/m3 .

Part A

Find the magnitude of the magnetic field needed to suspend the wire against gravity.

Part B

Find the direction of the magnetic field needed to suspend the wire against gravity. Assume the current points east.

Part A Find the magnitude of the magnetic field needed to suspend the wire against gravity. Express your answer with the appropriate units. Part B Find the direction of the magnetic field needed to suspend the wire against gravity. Assume the current points east. Point to south Point to north point to west point to east

Explanation / Answer

Here ,

Volume of wire = pi*r^2*L

Now , for Balancing Gravity and Magnetic force

Fm = Fg

BIL = m*g

B*0.11 * 2.50 = 8920*pi*(.000055)^2*0.11*9.8

solving for B

B = 3.322 *10^-4 T

the magnitude of the magnetic field needed to suspend the wire against gravity is 3.322 *10^-4 T

B)

Using Right Hand Rule ,

Field point in NORTH direction

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