Steven carefully places a 1.35-kg wooden block on a frictionless ramp, so that t

Question

Steven carefully places a 1.35-kg wooden block on a frictionless ramp, so that the block begins to slide M down the ramp from The ramp makes an angle of from the Which forces below do non-zero work on the block as it slides down the ramp? spring normal friction gravity How much total work has been done on the block after it slides down along the ramp a distance of 1.87 m? Number Nancy measures the speed of the wooden block after it has gone the 1.87 m down the ramp. Predict what she should measure. Number m/s Now, Steven again places the wooden block back at the top of the ramp, but this time he jokingly gives the block a big push before it slides down the ramp. If the block's initial speed is 2.00 m/s and the block again slides down the ramp 1.87 m, what should Nancy measure for the speed of the block this time?

Explanation / Answer

(a):

gravity does the non zero force on block.

(b):

total work done = Force*1.87

force = mg*sin(60.3)

total work done = 1.35*9.8*sin(60.3) = 11.492 Jules

(c):

v^2 = u^2 + 2as

u = 0

a = g*sin(60.3)

s = 1.87

v = sqrt(2*9.8*sin(60.3)) = 4.1262 m/s

(d):

u = 2 m/s

v = sqrt(2^2 +2*9.8*sin(60.3) ) = 4.5853 m/s

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