A) The two most prominent wavelengths in the light emitted by a hydrogen dischar

Question

A) The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486 nm (blue). Light from a hydrogen lamp illuminates a diffraction grating with 500lines/mm , and the light is observed on a screen 1.2m behind the grating

What is the distance between the first-order red and blue fringes?

Express your answer to two significant figures and include the appropriate units.

B) The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486nm (blue). Light from a hydrogen lamp illuminates a diffraction grating with 550lines/mm , and the light is observed on a screen 1.5m behind the grating.

What is the distance between the first-order red and blue fringes?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

We would use ze formula (d)(y/x)=m(wavelength).
Or when we make it solve for y, it becomes y=m(wavelength)(x)/d
Okays, so we use this formula twice, once using the wavelength for the red and once using the blue wavelength.
Red) y=1(6.56*10^-11)(1.2)(5*10^5)....Here y=3.936*10^-5
Blue) y=1(4.85*a0^-11)(1.2)(5*10^5)...Here y=2.912*10^-5
To find the distance between the red and the blue, we would now find the diffrence of the two answers:
(3.936*10^-5) - (2.912*10^-5) = 1.024*10^-5 = =1.0*10^-5 (2 significant figures)<----teh final answer forreal

B.Okays, so we use this formula twice, once using the wavelength for the red and once using the blue wavelength.
Red) y=1(6.56*10^-11)(1.5)(5*10^5)....Here y=4.92*10^-5
Blue) y=1(4.85*a0^-11)(1.5)(5*10^5)...Here y=3.64*10^-5
To find the distance between the red and the blue, we would now find the diffrence of the two answers:
(4.92*10^-5) - (3.64*10^-5) = 1.28*10^-5 <----teh final answer forreal =1.2*10^-5 (2 significant figures)

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