A 19.0N bucket is to be raised at a constant speed of 50 cm/s by a rope. Accordi

Question

A 19.0N bucket is to be raised at a constant speed of 50 cm/s by a rope. According to the information in the table (approximate breaking strengths), how many kilograms of cement can be put into this bucket without breaking the rope if it is made of:

Thin white string = 50N

1'/4 nylon clothesline rope = 4000 N

11mm perlon mountaineering rope = 3 x 10^4 N

1 1'/4 manila climbing rope = 6 x 10^4 N

1'/4 steel cable = 3 x 10^4 N

a) thin white string, m=?

b) 1/4 in. nylon clothesline, m=

c) manila climbing rope, m=

Explanation / Answer

The speed makes no difference. If acceleration is zero, the resultant force = 0, so
Upwards force = downwards force
Tension = (weight of bucket) + (weight of cement)
T = 24.0 + W

If the max value of T = 50N (thin white string):
50 = 24.0 + W
W = 26N
Since W = mg, m = W/g = 26/9.8 = 2.7kg

The max.load for the nylon clothesline is calculated the same way.

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