Unpolarized light of intensity 100 arb units falls on two polarizer sheets whose

Question

Unpolarized light of intensity 100 arb units falls on two polarizer sheets whose transmission axes are at right angles. A third polarizer is placed between the first two so that its axis makes a 62 degree angle with the axis of the first polarizer.

(a) What is the intensity of the light after the first polarizer?

(b) What is the intensity of the light between the inserted polarizer and the last polarizer?

(c) What is the intensity of the light after traveling through all three polarizers?

*Please show all steps*

Explanation / Answer

1] the intensity of the light after the 1st polariser = I0/2 = 50 arb units

2] now the light 2nd and the 3 rd polariser = I0cos^2theta = 50* cos^62* = 11.02 arb units

3] now the intensity after the last polariser = I0/2 = 11.02/2 = 5.51 arb units

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