A spherical mirror forms an image of an arrow at x = x 2 = -91 cm. The mirror is
ID: 1303414 • Letter: A
Question
A spherical mirror forms an image of an arrow at x = x2 = -91 cm. The mirror is represented in the drawing as a plane at x = 0. The tip of the object arrow is located at (x,y) = (x1,y1) = (-127 cm, 5.58 cm).
1)
What is f, the focal length of the mirror? If the mirror is concave f is positive. If the mirror is convex, f is negative.
cm
2)
What is y2, the y co-ordinate of the image of the tip of the arrow?
cm
Your submissions:
3)
The object arrow is now moved such that image distance doubles, i.e., ximage,new = -182 cm. What is yimage,new, the new y co-ordinate of the image of the tip of the arrow?
cm
Your submissions:
4)
The object arrow is now moved to x = x1,new = -26 cm. What is y2,new, the new y co-ordinate of the image of the arrow?
cm
Your submissions:
5)
Which of the rays in the diagram is not reflected as shown?
(a)
(b)
(c)
Explanation / Answer
1) 1/p + 1/q = 1/f
1/127 + 1/91 = 1/f
f= 53 cm
2) y2 = -q/p y1 = -91/127*5.58=-4.00 cm
3)
1/p + 1/182 = 1/53
p=74.78
so y2 = -q/p y1 = -182/74.78*5.58= -13.58 cm
4) 1/q + 1/26 = 1/53
q=-51.04
y2 = -51.04/26*5.58=-10.95 cm
5) b)
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