6 C 14 (14.003242 u) decays to 7 N 14 (14.002525 u) by ? emission. ( -1 e 0 =0.0

Question

6C14(14.003242 u) decays to 7N14 (14.002525 u) by ? emission. (-1e0=0.000549 u)

a. Write a nuclear equation for this decay process. Use a minus sign and greater than sign -> for the right arrow symbol for the decay in the equation. Use no parentheses or spaces. Write the elements as 6C14, 7N14, -1e0.
Answer
b. Which material is called the Parent Nucleus?
  Answer
c. Which material is called the Daughter Nucleus?
  Answer
d. Calculate the total nuclear mass before the decay.
mtotal=Answer u
e. Calculate the total nuclear mass after the decay.
  mtotal=Answer u
f. Calculate the change in nuclear mass. Where does this energy go?
?m=Answer u

This energy goes to Answer of the particles.
g. Calculate how much energy is given off by this nuclear decay.

?E=Answer MeV

Explanation / Answer

A)6C14--->7N14+-1e0

B)6C14

C)7N14

D)14.003242u

E)14.003074u

F)?m=14.002525+0.000549-14.003242

=-0.000168u

G)?E=?mc^2

=0.000168 u*c^2

1 amu = 931.4941 MeV/c2

=0.000168*931.941

=0.156 Mev

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