A. Calculate the mass defect of the nitrogen nucleus 14 7N. The mass M N of neut

Question

A. Calculate the mass defect of the nitrogen nucleus 14 7N. The mass MN of neutral 14 7N is equal to 14.003074 atomic mass units.

B. Calculate the binding energy EB of the nitrogen nucleus 14 7N.

C. Calculate the binding energy per nucleon of the nitrogen nucleus 14 7N.

D. Calculate the mass defect of the helium nucleus 42He. The mass of neutral 42He is given by MHe=4.002603u.

E. Calculate the binding energy EB of the helium nucleus 42He.

F. Calculate the binding energy per nucleon of the helium nucleus 42He.

Explanation / Answer

A. 14 N 7 have 7 protons and (14-7) = 7 neutruons

so mass of its constituents = (7*1.007825)+(7*1.00866) = 14.1153

mass defect = 14.1153--14.003074 = 0.11231 amu

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B. BE = mass defect *931.5

BE = 0.11231*931.5 = 104.62 MeV

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c. BE/A = 104.62/14 = 7.47 MeV/u

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d. 4 He 2 has 2 protons and 2 nutrons

= (2* 1.007825)+ (2*1 .00866)

= 4.03297 amu

mass defect =4.03297 - 4.002603 = 0.030367 u

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E. BE = 0.030367*931.5 = 28.2868 MeV

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F. BE/A = 28.28689/4 = 7.0717 MeV/u

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